- We first started by measuring the mass of our aluminum foil in grams (g).
- Next, we measured the side lengths of the piece of aluminum foil--length (l) & width (w)
- We then used to different formulas- D = M/V (density = mass/volume) & V = l x w x h (volume = length x width x height)
- We were given the estimated density of foil, which is 2.70 g/cm
- Now all that's left to do is plug in your numbers! **listing your knowns and unknowns would be a good idea. It's an excellent way to see the problem clearly**
M = 0.88 g
V = ?
l = 15.59 cm
w = 17.00 cm
h = ?
First step is to solve for V
D = M/V
2.70 g/cm3 = 0.88 g/V <---- divide both sides by 0.88 g
0.326 cm 3 = V
Next solve for height (thickness)
V = l x w x h
0.326 cm3 = 15.59 cm x 17.00 cm x h
0.326 cm3 = 265.03 cm2 x h <---- divide both sides by 265.03 cm2
h = 0.00123 cm <---- write this number in the correct number of sig figs (in this case, 2)
h = 0.0012 cm <---- write it in scientific notation
h = 1.2 x 10-3cm
So through these easy steps, you'll be well on your way to determining a close estimate to the thickness of a piece of aluminum foil! Hoorah!
Your calculation in your first step is incorrect. 2.70/0.88 equals 3.0681.... So, how did you get 0.326?
ReplyDeleteLol you cross multiply then solve for v and then you get the same answer. Haha 2016
Deletethank you this was helpful for a lab write up we had to do with procedures and a table
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ReplyDeletesooooooooooooooooooo.......................!!! WHATS THE ANSWER
ReplyDeletesooooooooooooooooooo.......................!!! WHATS THE ANSWER
ReplyDeleteactually you don't need the answer. It is shown up their how to do it and it is set up with all he formulas. Also, it is step by step walked through. You can do it on your own with paper and calculator now.
DeleteThank you for sharing your insights. It is very informative and helpful. I might use this as inspiration for my projects. Keep it up! I’m looking forward to your updates.
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